Electric Field & Electric Field Intensity — A/L Physics

How do I practise Electric Field & Electric Field Intensity?

1 question with a worked solution

1. Two large parallel conducting plates separated by a distance d = 2.0 cm in a vacuum are maintained at a potential difference V = 200 V. What is the magnitude of the electrostatic acceleration experienced by an electron (charge e = 1.6 × 10⁻¹⁹ C, mass m = 9.1 × 10⁻³¹ kg) placed between the plates?
   1. A) 8.80 × 10¹⁴ m s⁻²
   2. B) 1.76 × 10¹³ m s⁻²
   3. C) 3.52 × 10¹⁵ m s⁻²
   4. D) 1.76 × 10¹⁵ m s⁻²
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   Correct answer: D) 1.76 × 10¹⁵ m s⁻²

   Uniform electric field between plates: E = V / d = 200 V / (0.02 m) = 1.0 × 10⁴ V m⁻¹. Electrostatic force on electron: F = e E = (1.6 × 10⁻¹⁹ C) × (1.0 × 10⁴ V m⁻¹) = 1.6 × 10⁻¹⁵ N. Acceleration a = F / m = (1.6 × 10⁻¹⁵ N) / (9.1 × 10⁻³¹ kg) ≈ 1.76 × 10¹⁵ m s⁻².

   Show worked solution

   Step 1: E = V / d = 200 / 0.02 = 10,000 N C⁻¹. Step 2: F = e·E = 1.6 × 10⁻¹⁹ × 10⁴ = 1.6 × 10⁻¹⁵ N. Step 3: a = F / m = 1.6 × 10⁻¹⁵ / 9.1 × 10⁻³¹ ≈ 1.76 × 10¹⁵ m s⁻². Answer: 1.76 × 10¹⁵ m s⁻².
   Modelled on: the A/L Physics examination pattern

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Where does Electric Field & Electric Field Intensity fit in the syllabus?

Unit 6.2 · Year 1 · Term 3