Series & Parallel Circuits — A/L Physics

How do I practise Series & Parallel Circuits?

1 question with a worked solution

1. Three identical resistors each of resistance R = 12 Ω are connected in a network such that two resistors are in parallel, and this combination is connected in series with the third resistor. What is the equivalent resistance of the entire network between terminals?
   1. A) 18 Ω
   2. B) 36 Ω
   3. C) 24 Ω
   4. D) 8 Ω
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   Correct answer: A) 18 Ω

   The two parallel resistors have an equivalent resistance of R_p = (12 × 12) / (12 + 12) = 6 Ω. This combination is in series with the third 12 Ω resistor: R_eq = R_p + R₃ = 6 Ω + 12 Ω = 18 Ω.

   Show worked solution

   Step 1: Parallel combination: R_p = (12 × 12) / (12 + 12) = 6 Ω. Step 2: Total equivalent resistance: R_eq = 6 Ω + 12 Ω = 18 Ω. Answer: 18 Ω.
   Modelled on: the A/L Physics examination pattern

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Where does Series & Parallel Circuits fit in the syllabus?

Unit 7.4 · Year 2 · Term 1