Generators & Motors — A/L Physics
Aligned with the NIE syllabus
How do I practise Generators & Motors?
1 question with a worked solution
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A direct-current (DC) electric motor with an armature resistance of 1.0 Ω is operated from a 200 V DC supply. When running at full operating speed, the armature draws a current of 10 A. What back electromotive force (back EMF, Eb) is developed in the spinning armature?
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Correct answer: D) 190 V
In a running DC motor, the applied voltage V overcomes the back EMF Eb and supplies the ohmic drop across armature resistance: V = Eb + Ia Ra. Rearranging: Eb = V - Ia Ra = 200 V - (10 A × 1.0 Ω) = 200 V - 10 V = 190 V.
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Step 1: Motor voltage equation: V = Eb + Ia · Ra. Step 2: Eb = V - Ia · Ra = 200 - (10 × 1.0) = 190 V. Answer: 190 V.Modelled on: the A/L Physics examination pattern
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Where does Generators & Motors fit in the syllabus?
Unit 8.7 · Year 2 · Term 1
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