Electromagnetic Induction — A/L Physics

How do I practise Electromagnetic Induction?

1 question with a worked solution

1. A horizontal straight conducting rod of length 0.40 m moves horizontally at right angles to its length with a velocity of 5.0 m s⁻¹ through a vertical downward magnetic field B = 0.30 T. What motional electromotive force (EMF) is induced across the ends of the rod?
   1. A) 1.20 V
   2. B) 0.60 V
   3. C) 0.30 V
   4. D) 0.15 V
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   Correct answer: B) 0.60 V

   The motional electromotive force induced across a conductor moving perpendicular to a magnetic field is given by Faraday's / Lorentz relation: ε = B l v. Substituting: ε = 0.30 T × 0.40 m × 5.0 m s⁻¹ = 0.60 V.

   Show worked solution

   Step 1: Formula: ε = B · l · v. Step 2: ε = 0.30 × 0.40 × 5.0 = 0.60 V. Answer: 0.60 V.
   Modelled on: the A/L Physics examination pattern

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Where does Electromagnetic Induction fit in the syllabus?

Unit 8.3 · Year 2 · Term 1