Electric Current & Charge Flow — A/L Physics
Aligned with the NIE syllabus
How do I practise Electric Current & Charge Flow?
1 question with a worked solution
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A copper wire of cross-sectional area A = 1.0 × 10⁻⁶ m² carries a steady current I = 3.2 A. If the free electron density in copper is n = 8.0 × 10²⁸ m⁻³ and electron charge is e = 1.6 × 10⁻¹⁹ C, what is the drift velocity vd of conduction electrons in the wire?
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Correct answer: A) 2.5 × 10⁻⁴ m s⁻¹
The relationship between electric current and electron drift velocity is I = n A e vd. Rearranging: vd = I / (n A e) = 3.2 A / [(8.0 × 10²⁸ m⁻³) × (1.0 × 10⁻⁶ m²) × (1.6 × 10⁻¹⁹ C)] = 3.2 / (1.28 × 10⁴) = 2.5 × 10⁻⁴ m s⁻¹.
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Step 1: Formula: vd = I / (n · A · e). Step 2: vd = 3.2 / (8.0 × 10²⁸ × 1.0 × 10⁻⁶ × 1.6 × 10⁻¹⁹) = 3.2 / 12,800 = 2.5 × 10⁻⁴ m s⁻¹. Answer: 2.5 × 10⁻⁴ m s⁻¹.Modelled on: the A/L Physics examination pattern
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Where does Electric Current & Charge Flow fit in the syllabus?
Unit 7.1 · Year 2 · Term 1
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