Square Root — O/L Mathematics
Aligned with the NIE syllabus
How do I practise Square Root?
2 questions with worked solutions
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Find the square root of 53 to the first decimal place by division or approximation method.
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Correct answer: B) 7.3
Since 7² = 49 and 8² = 64, √53 lies between 7 and 8. Testing 7.3² = 53.29 and 7.2² = 51.84. 53 is closer to 53.29, so √53 ≈ 7.3 to one decimal place.
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Step 1: Identify bounding perfect squares: 49 < 53 < 64, so 7 < √53 < 8. Step 2: Linear interpolation approximation: 7 + (53 - 49)/(64 - 49) = 7 + 4/15 ≈ 7 + 0.27 = 7.27. Step 3: Square check: 7.3² = 53.29 (difference +0.29); 7.2² = 51.84 (difference -1.16). Step 4: 53 is much closer to 53.29 than 51.84. Rounding to the first decimal place yields 7.3. Answer: 7.3.Modelled on: the O/L Mathematics examination pattern -
Find the square root of 1296 using prime factorisation.
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Correct answer: D) 36
As a product of prime factors, 1296 = 2⁴ × 3⁴. Taking a square root halves each index, so √1296 = 2² × 3² = 4 × 9 = 36. Check: 36 × 36 = 1296.
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Step 1: Write 1296 as a product of prime factors: 1296 = 2 × 2 × 2 × 2 × 3 × 3 × 3 × 3 = 2⁴ × 3⁴. Step 2: Halve each index: √1296 = 2² × 3². Step 3: Multiply: 4 × 9 = 36. Step 4: Check: 36² = 1296. Answer: 36.Modelled on: the O/L Mathematics examination pattern
Next in the syllabus
Where does Square Root fit in the syllabus?
Grade 10 · Term 1
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