Fluid Statics — A/L Physics

How do I practise Fluid Statics?

1 question with a worked solution

1. A vertical U-tube containing mercury (density 13,600 kg m⁻³) has water (density 1,000 kg m⁻³) poured into one arm to a height of 27.2 cm. What is the difference in mercury levels between the two arms?
   1. A) 2.0 cm
   2. B) 27.2 cm
   3. C) 1.36 cm
   4. D) 4.0 cm
   Check my answer

   Correct answer: A) 2.0 cm

   At the horizontal datum level passing through the water-mercury interface: Pressure in water arm = Pressure in mercury arm. Hence, h_w ρ_w g = h_m ρ_m g => h_m = h_w (ρ_w / ρ_m) = 27.2 cm × (1,000 / 13,600) = 27.2 / 13.6 = 2.0 cm.

   Show worked solution

   Step 1: Balance pressures at interface: h_w · ρ_w = h_m · ρ_m. Step 2: h_m = (27.2 cm × 1,000 kg m⁻³) / 13,600 kg m⁻³ = 2.0 cm. Answer: 2.0 cm.
   Modelled on: the A/L Physics examination pattern

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Where does Fluid Statics fit in the syllabus?

Unit 2.6 · Year 1 · Term 1