Equation of a straight line — A/L Combined Mathematics

How do I practise Equation of a straight line?

1 question with a worked solution

1. What is the equation of the straight line passing through the point (2, 3) with gradient m = -1/2?
   1. A) 2x + y - 7 = 0
   2. B) x - 2y + 4 = 0
   3. C) x + 2y - 8 = 0
   4. D) x + 2y - 4 = 0
   Check my answer

   Correct answer: C) x + 2y - 8 = 0

   Using the point-slope form y - y₁ = m(x - x₁): y - 3 = (-1/2)(x - 2) => 2(y - 3) = -(x - 2) => 2y - 6 = -x + 2 => x + 2y - 8 = 0.

   Show worked solution

   Step 1: Point-slope form: y - 3 = -½(x - 2). Step 2: 2y - 6 = -x + 2 => x + 2y - 8 = 0. Answer: x + 2y - 8 = 0.
   Modelled on: the A/L Combined Mathematics examination pattern

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Where does Equation of a straight line fit in the syllabus?

Year 1 · Term 3