Evolution and gene frequencies — A/L Biology
Aligned with the NIE syllabus
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1 question with a worked solution
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In a population in Hardy-Weinberg equilibrium, the frequency of individuals affected by an autosomal recessive condition is 0.04. What is the frequency of heterozygous carriers in this population?
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Correct answer: C) 0.32
q² = 0.04 → q = 0.2. Since p + q = 1, p = 1 - 0.2 = 0.8. Frequency of heterozygous carriers (2pq) = 2 × 0.8 × 0.2 = 0.32 (32%).
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Step 1: Recessive phenotype frequency q² = 0.04. Step 2: Recessive allele frequency q = √0.04 = 0.2. Step 3: Dominant allele frequency p = 1 - q = 1 - 0.2 = 0.8. Step 4: Heterozygote carrier frequency = 2pq = 2(0.8)(0.2) = 0.32. Answer: 0.32.Modelled on: the A/L Biology examination pattern
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Where does Evolution and gene frequencies fit in the syllabus?
Year 1 · Term 2
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